Investigate r = a + b cos(kθ) for various values of a, b, and k.
Lets start by setting a and b equal to 1 and observing how different values of k affect the graph of r = a + b cos(kθ) .
r = 1 + 1 cos(2θ)
r = 1 + 1 cos(3θ)
r = 1 + 1 cos(4θ)
r = 1 + 1 cos(5θ)
Our parameter k seems to represent the number of pedals. ± a/b appears to represent the y-intercepts of the graphs with an odd number of petals.
Lets see if this holds for other values of a and b when k =5.
a = b = 2
r = 2 + 2 cos(5θ)
a = b = 5
r = 5 + 5 cos(5θ)
a = b = 10
r = 10 + 10 cos(5θ)
As a/b increase the shape of the graph stays the same, but this size of rose increases.
We can conclude:
Parameter k represents the number of petals in the rose.
When k is odd and a=b, ± a/b represent the y-intercepts.
When k is even, ± a/b does not represent the y-intercepts.
Next, lets looks at r = b cos(kθ) for various values of b and k.
Let b=1 and k=3
r = 1 cos(3θ)
Parameter k still seems to represent the number of petals, but +b appears to represent the x-intercept instead of the y-intercept.
Lets look at what happens when we change b, but hold k constant.
The video below illustrates -5 ≤ b ≤ 5.
Lets look at what happens when we change k and hold b constant.
r = 1 cos(2θ)
r = 1 cos(5θ)
r = 1 cos(6θ)
Notice that when parameter k is even, there are 2k number of petals. Additionally, x-intercepts appear at –b and +b when k is even.
We can conclude:
When parameter k is odd, k represents the number of petals in the rose.
+b represents the x-intercept.
When parameter k is even, 2k represents the number of petals in the rose.
– b and +b represent the x-intercepts.
What do you think will happen if cos(kθ) is replaced with sin(kθ) in both equations.
r = 1 + 1 sin(3θ)
r =1 sin(3θ)
The overall shape and size are the same, but it appears that the graph has been rotated 90° to the right.Click here to return to Lacy's homepage.